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Showing posts with label Working with DATETIME and SMALLDATETIME in SQL Server. Show all posts
Showing posts with label Working with DATETIME and SMALLDATETIME in SQL Server. Show all posts

Wednesday, July 20, 2011

MSSQL Server Tips and Tricks

The following are a wide range of tips and tricks I have collected over the years working with various versions or Microsoft's SQL Server. I always enjoy finding little snippets of code which are both simple and powerful. Why write complicated routines when one or two lines of code can do it?
Although you may very well find the following code useful, I don't really want small posts like this from detracting from the overall purpose of my blog, which is to help me develop my writing skills. I am therefore going to create a section on this bloggie called my Code Notebook which will hopefully serve two purposes:
  1. It will provide me with an area to note down and share pieces of code which I am proud of creating and,
  2. It will keep the main focus of the bloggie on improving my writing.
So without further ado, I present to you my SQL Server Tips and Tricks...

Date Only

Quite a useful function for producing or saving only the date part of the smalldatetime datatype. This can be useful if you only need to store the date or you need to group some results by dateonly.
Select
Convert([smalldatetime],floor(Convert([float],getdate(),(0))),(0))

Produce a Row or Table Checksum

This can be useful for checking if any of the contents of a row or table has changed without saving the entire contents of row or table.
Table Checksum
Select CheckSum_Agg(Binary_CheckSum(*)) From Table With (NOLOCK)
Row Checksum
Select CheckSum_Agg(Binary_CheckSum(*)) From Table Where Column = Value

Reindex an entire database

EXEC [sp_MSforeachtable] @command1 = "RAISERROR('DBCC DBREINDEX(''?'') ...',10,1) WITH NOWAIT DBCC DBREINDEX('?')"

Count Character in a String

This very simple statement allows you to count how many times a certain character appears in a string.
Select Len('///xxx') - Len(Replace('///xxx', '/', ''))

Single & Multi User Mode

By default, a database is set to Multi User Mode, allowing more than one connection to connect to the database at a time. However, it may prove useful at times, for example database maintenance, to restrict the database to only 1 connection. This allows that 1 user to carry out work on the database without any locks.
ALTER DATABASE MyDatabase SET SINGLE_USER

ALTER DATABASE MyDatabase SET MULTI_USER

Smart Date Ranges

Find records which date falls somewhere inside the current week.
where dateadd( week, datediff( week, 0, TransDate ), 0 ) =
dateadd( week, datediff( week, 0, getdate() ), 0 )
Find records which date occurred last week.
where dateadd( week, datediff( week, 0, TransDate ), 0 ) =
dateadd( week, datediff( week, 0, getdate() ) - 1, 0 )
Returns the date for the beginning of the current week.
select dateadd( week, datediff( week, 0, getdate() ), 0 )
Returns the date for the beginning of last week.
select dateadd( week, datediff( week, 0, getdate() ) - 1, 0 )

Drop all Database Connections

Although this could be a very dangerous script to run, it is very useful when you need to do some maintenance on a database and there are some rouge connections open stopping you from doing so. The script will run through all users currently connection to the specified database and kill their connection.
Use Master
Go
Declare @dbname sysname
Set @dbname = 'name of database you want to drop connections from'
Declare @spid int
Select @spid = min(spid) from master.dbo.sysprocesses
where dbid = db_id(@dbname)
While @spid Is Not Null
Begin
        Execute ('Kill ' + @spid)
        Select @spid = min(spid) from master.dbo.sysprocesses
        where dbid = db_id(@dbname) and spid > @spid
End
If anyone know  more tips or tricks please share them with me...

Wednesday, September 15, 2010

How To Convert Database of SQL Server 2008 to SQL Server 2005?

Requirements

If you are trying to restore database backup of SQL Server 2008 to SQL Server 2005, you are bound to fail. Database backup of SQL Server 2008 is not compatible backward, you cannot restore it to SQL Server 2005. The following is a solution to convert databases of SQL Server 2008 to 2005

Step by Step Guide

1) Start convert wizard

Open SQL Server Management Studio2008. in 'Object Explorer', right click the database that you want to convert. Select 'Tasks' > 'Generate Scripts...'.

Change Hyper-V Default Folders Step 1

2) Next

Click 'Next'.

Change Hyper-V Default Folders Step 1

3) Select database and objects

Select the database that you want to convert, and check on 'Scripts all objects in the selected databases'

Change Hyper-V Default Folders Step 2

4) Convert Options

Set options:

'Script for Server Version' = 'SQL Server 2005' 'Script Data' = 'True' 'Scirpt Database Create' = 'True'     
Change Hyper-V Default Folders Step 2

5) Output Option

Select option 'Script to file', 'Single file' and 'Unicode text'.

Change Hyper-V Default Folders Step 1

6) 'Finish'

View summary and click 'Finish'.

Change Hyper-V Default Folders Step 1

7) Result

Now you got a complete database creation script with data. It can be executed on target database server.

Change Hyper-V Default Folders Step 1

8) Amend Script

Open the generated script in SQL Server Management Studio 2005. Find the following section and amend the path to proper data folder
    CREATE DATABASE [StockTraderDB] ON  PRIMARY  ( NAME = N'StockTraderDB',  FILENAME = N'c:\Program Files\Microsoft SQL Server\MSSQL10.SQLEXPRESS\MSSQL\DATA\StockTraderDB.mdf ,  SIZE = 4352KB , MAXSIZE = UNLIMITED, FILEGROWTH = 1024KB )  LOG ON  ( NAME = N'StockTraderDB_log',  FILENAME = N'c:\Program Files\Microsoft SQL Server\MSSQL10.SQLEXPRESS\MSSQL\DATA\StockTraderDB_log.LDF',  SIZE = 6272KB , MAXSIZE = 2048GB , FILEGROWTH = 10%) 

9) Execute the Script

When finished, You should get converted database of SQL Server 2005

Related Resources

Wednesday, August 4, 2010

Total Functions in SQL Server 2005

SQL Server built-in functions are either deterministic or nondeterministic. Functions are deterministic when they always return the same result any time they are called by using a specific set of input values. Functions are nondeterministic when they could return different results every time they are called, even with the same specific set of input values.

Functions that take a character string input and return a character string output use the collation of the input string for the output. Functions that take no character inputs and return a character string use the default collation of the current database for the output. Functions that take multiple character string inputs and return a character string use the rules of collation precedence to set the collation of the output string

In this article I am going to explain about some SQL Server 2005 functions with examples. A function performs an operation and returns a value. A function consists of the function name, followed by a set of parenthesis that contains any parameter or arguments required by the function. If a function requires two or more arguments you can separate them with commas.

Here are going to discuss about some string functions, numeric functions and date/time functions.

Note - I am using my own database table for examples. See database table in figure 1.

Figure 1.

String Functions

1. LEN (string) - Returns the number of characters of the specified string expression, excluding trailing blanks.

Example:

use Vendor

GO

Select LEN('Raj'), LEN('Raj ') FROM VENDOR WHERE VendorFName='Raj'

GO

LEN doesn't count length of spaces. So result looks like this.

2. LTRIM (string) - LTRIM function to return a character expression after removing leading spaces.

Example:

use Vendor

GO

use Vendor

SELECT LTRIM(' Raj')

FROM VENDOR WHERE VendorFName='Raj'

Go

3. RTRIM (string) - RTRIM function to return a character expression after removing trailing spaces.

Example:

use Vendor

GO

use Vendor

Select RTRIM('Raj ')

FROM VENDOR WHERE VendorFName='Raj'

GO

4. LEFT (string, length) - Returns the specified number of characters from the beginning of the string.

Example:

use Vendor

SELECT VendorFName, VendorLName, LEFT(VendorFName, 1) + LEFT (VendorLName, 1) AS Initials FROM Vendor

5. RIGTH (string, length) - Returns the specified number of characters from the end of the string.

Example:

use Vendor

SELECT VendorFName, VendorLName, RIGHT(VendorFName, 1) + RIGHT (VendorLName, 1) AS Initials FROM Vendor

6. SUBSTRING (string, start, length) - Returns the specified number of characters from the string starting at the specified position.

Example:

use Vendor

GO

SELECT SUBSTRING('beniwal', 2, 2) FROM VENDOR WHERE VendorFName='Raj'

GO

7. REPLACE (search, find, replace) - Returns the search string with all occurrences of the find string replaced with the replace string.

Example:

use Vendor

GO

use Vendor

SELECT REPLACE('Beniwal', 'Beniwal', 'Choudhary')

FROM VENDOR WHERE VendorFName='Raj'

GO

8. REVERSE (string) - Returns the string with the character in reverse order.

Example:

use Vendor

GO

use Vendor

SELECT REVERSE('Raj')

FROM VENDOR WHERE VendorFName='Raj'

GO

9. CHARINDEX (find, search [, start]) - Returns an integer that represents the position of the first occurrence of the find string in the search string starting at the specified position. If the starting position isn't specified, the search starts at the beginning of the string. If the staring isn't found, the functions returns zero.

Example:

use Vendor

GO

use Vendor

SELECT CHARINDEX('w', 'Beniwal')

FROM VENDOR WHERE VendorFName='Raj'

GO

10. PATINDEX (find, search [, start]) - PATINDEX is useful with text data types; it can be used in a WHERE clause in addition to IS NULL, IS NOT NULL, and LIKE (the only other comparisons that are valid on text in a WHERE clause). If either pattern or expression is NULL, PATINDEX returns NULL when the database compatibility level is 70. If the database compatibility level is 65 or earlier, PATINDEX returns NULL only when both pattern and expression are NULL.

Example:

use Vendor

GO

use Vendor

SELECT PATINDEX('%Krew%', VendorLName)

FROM VENDOR WHERE VendorId=5

GO

11. LOWER (string) - Returns the string converted to lowercase letters.

Example:

use Vendor

GO

use Vendor

SELECT LOWER('Raj')

FROM VENDOR WHERE VendorFName='Raj'

GO

12. UPPER (string) - Returns the string converted to uppercase letters.

Example:

use Vendor

GO

use Vendor

SELECT UPPER('Raj')

FROM VENDOR WHERE VendorFName='Raj'

GO

13. SPACE (integer) - Returns the string with the specified number of space characters (blanks).

Example:

use Vendor

GO

use Vendor

SELECT VendorFName + ',' + SPACE(2) + VendorLName

FROM VENDOR WHERE VendorFName='Raj'

GO

Numeric Functions

1 ROUND (number, length, [function]) - Returns the number rounded to the precision specified by length. If length is positive, the digits to the right of the decimal point are rounded. If it's negative the digits to the left of the decimal point are rounded. To truncate the number rather than round it code a non zero value for function.

Example:

USE Vendor

GO

--Used Round the estimates

SELECT ROUND(123.9994, 3), ROUND(123.9995, 3)

--Use ROUND and rounding approximations

SELECT ROUND(123.4545, 2), ROUND(123.45, -2)

--Use ROUND to truncate

SELECT ROUND(150.75, 0), ROUND(150.75, 0, 1)

GO

2 ISNUMERIC(expressions) - Returns a value of 1 (true) if the expression is a numeric value; returns a values of 0 (false) otherwise.

Example:

USE Vendor

GO

SELECT IsNumeric(VendorId) FROM Vendor

SELECT ISNumeric(VendorFName) FROM Vendor

GO

3 ABS (number) - Returns the absolute value of number.

Example:

USE Vendor

GO

SELECT ABS(-1.0), ABS(0.0), ABS(1.0)

GO

4 CEILING (number) - Returns the smallest integer that is greater than or equal to the number.

Example:

USE Vendor

GO

SELECT CEILING($123.45),CEILING($-123.45), CEILING($0.0)

GO

5 FLOOR (number) - Is an expression of the exact numeric or approximate numeric data type category, except for the bit data type.

Example:

USE Vendor

GO

SELECT FLOOR(123.45), FLOOR(-123.45), FLOOR($123.45)

GO

6 SQUARE (float_number) - Returns the square of the given expression.

Example:

USE Vendor

GO

DECLARE @h float, @r float

SET @h = 5

SET @r = 1

SELECT PI()* SQUARE(@r)* @h AS 'Cyl Vol'

GO

7 SQRT (float_number) - Returns a square root of a floating-point number.

Example:

USE Vendor

GO

DECLARE @myvalue float

SET @myvalue = 1.00

WHILE @myvalue < 10.00

BEGIN

SELECT SQRT(@myvalue)

SELECT @myvalue = @myvalue + 1

END

GO

8 RAND ([seed]) - Returns a random float value from 0 through 1.

Seed

Is an integer expression (tinyint, smallint, or int) that specifies the seed value. If seed is not specified, Microsoft SQL Server 2000 assigns a seed value at random. For a given seed value, the result returned is always the same.

Example:

USE Vendor

GO

DECLARE @counter smallint

SET @counter = 1

WHILE @counter < 5

BEGIN

SELECT RAND() Random_Number

SET NOCOUNT ON

SET @counter = @counter + 1

SET NOCOUNT OFF

END

GO

Date/Time Functions:

1 GetDate () - Returns the current system date and time in the Microsoft SQL Server standard internal format for date time values.

Example:

USE Vendor

GO

SELECT GetDate()

GO

2 GETUTCDATE() - Returns the current UTC date and time based on the system's clock and time zone setting. UTC (Universal Time Coordination) is the same as Greenwich Mean Time.

Example:

USE Vendor

GO

SELECT GETUTCDATE()

GO

3 DAY (date) - Returns the day of the month as an integer.

Example:

USE Vendor

GO

SELECT DAY('03/12/1998') AS 'Day Number'

GO

4 MONTH (date) - Returns the month as an integer.

Example:

USE Vendor

GO

SELECT "Month Number" = MONTH('03/12/1998')

SELECT MONTH(0), DAY(0), YEAR(0)

GO

5 YEAR (date) - Returns the 4-digit year as an integer.

Example:

USE Vendor

GO

SELECT "Year Number" = YEAR('03/12/1998')

GO

6 DATENAME (datepart, date) - Returns an integer representing the specified date part of the specified date.

Example:

USE Vendor

GO

SELECT DATENAME(month, getdate()) AS 'Month Name'

GO

7 DATEPART(datepart, date)

Is the parameter that specifies the part of the date to return? The table lists date parts and abbreviations recognized by Microsoft SQL Server.

Datepart

Abbreviations

year

yy, yyyy

quarter

qq, q

month

mm, m

dayofyear

dy, y

day

dd, d

week

wk, ww

weekday

dw

hour

hh

minute

mi, n

second

ss, s

millisecond

ms

The week (wk, ww) datepart reflects changes made to SET DATEFIRST. January 1 of any year defines the starting number for the week datepart, for example: DATEPART(wk, 'Jan 1, xxxx') = 1, where xxxx is any year.

The weekday (dw) datepart returns a number that corresponds to the day of the week, for example: Sunday = 1, Saturday = 7. The number produced by the weekday datepart depends on the value set by SET DATEFIRST, which sets the first day of the week.

Date

Is an expression that returns a datetime or smalldatetime value, or a character string in a date format. Use the datetime data type only for dates after January 1, 1753. Store dates as character data for earlier dates. When entering datetime values, always enclose them in quotation marks. Because smalldatetime is accurate only to the minute, when a smalldatetime value is used, seconds and milliseconds are always 0.

If you specify only the last two digits of the year, values less than or equal to the last two digits of the value of the two digit year cutoff configuration option are in the same century as the cutoff year. Values greater than the last two digits of the value of this option are in the century that precedes the cutoff year. For example, if two digit year cutoff is 2049 (default), 49 is interpreted as 2049 and 2050 is interpreted as 1950. To avoid ambiguity, use four-digit years.

For more information about specifying time values, see Time Formats. For more information about specifying dates, see datetime and smalldatetime.

Example :

USE Vendor

GO

SELECT GETDATE() AS 'Current Date'

SELECT DATEPART(month, GETDATE()) AS 'Month Number'

SELECT DATEPART(m, 0), DATEPART(d, 0), DATEPART(yy, 0)

GO

8 DATEADD (datepart, number, date) - Returns the date that results from adding the specified number of datepart units to the date.

Example -

USE Vendor

GO

SELECT DATEADD(day, 21, PostedDate) AS timeframe FROM Vendor

GO

9 DATEDIFF (datepart, startdate, enddate) - Returns the number of datepart units between the specified start date and end date.

Example:

USE Vendor

GO

SELECT DATEDIFF(day, posteddate, getdate()) AS no_of_days

FROM Vendor WHERE VendorFName='Raj'

GO

10 ISDATE (expression) - Returns a value of 1(true) if the expression is a valid date/time value; returns a value of 0(false) otherwise.

Example:

USE Vendor

GO

DECLARE @datestring varchar(8)

SET @datestring = '12/21/98'

SELECT ISDATE(@datestring)

GO

More Functions -

1 CASE - Evaluate a list of conditions and returns one of multiple possible return expressions.

CASE has two formats:

  • The simple CASE function compares an expression to a set of simple expressions to determine the result.
  • The searched case function evaluates a set of boolean expressions to determine the result.

Syntax:

Simple CASE function:

CASE input_expression

WHEN when_expression THEN result_expression

[...n]

[

ELSE else_result_expression

]

END

Searched CASE function:

CASE

WHEN Boolean_expression THEN result_expression

[...n]

[

ELSE else_result_expression

]

END

Example:

use Vendor

GO

SELECT VendorId, VendorFName, VendorLName,

CASE VendorId

WHEN 1 THEN 'This is vendor id one'

WHEN 2 THEN 'This is vendor id two'

WHEN 3 THEN 'This is vendor id three'

WHEN 4 THEN 'This is vendor id four'

WHEN 5 THEN 'this is vendor id five'

END AS PrintMessage

FROM Vendor

2 COALESCE - Returns the first nonnull expression among its arguments.

Syntax:

COALESCE (expression [...n])

Example:

use Vendor

GO

SELECT PostedDate, COALESCE(PostedDate, '1900-01-01') AS NewDate

FROM Vendor

3 ISNULL - Replaces NULL with the specified replacement value.

Syntax:

ISNULL (check_expression, replacement_value)

Example:

use Vendor

GO

SELECT PostedDate, ISNULL(PostedDate, '1900-01-01') AS NewDate

FROM Vendor

GO

4 GROUPING - Is an aggregate function that causes an additional column to be output with a value of 1 when the row is added by either the CUBE or ROLLUP operator, or 0 when the row is not the result of CUBE or ROLLUP.Grouping is allowed only in the select list associated with a GROUP BY clause that contains either the CUBE or ROLLUP operator.

Syntax: GROUPING (column_name)

Example -

Use Vendor

GO

SELECT royality, SUM(advance) 'total advance', GROUPING(royality) 'grp'

FROM advance

GROUP BY royality

WITH ROLLUP

5 ROW_Number() - Returns the sequential number of a row within a partition of a result set, starting at 1 for the first row in each partition

Syntax: ROW_NUMBER ( ) OVER ([] )

Note: The ORDER BY in the OVER clause orders ROW_NUMBER. If you add an ORDER BY clause to the SELECT statement that orders by a column(s) other than 'Row Number' the result set will be ordered by the outer ORDER BY.

Example:

Use Vendor

GO

SELECT VendorFName, VendorLName,

ROW_Number() Over(ORDER BY PostedDate) AS 'Row Number'

FROM Vendor

GO

6 RANK () - Returns the rank of each row within the partition of a result set. The rank of a row is one plus the number of ranks that come before the row in question.

Syntax: RANK ( ) OVER ([<>] <>)

Arguments: <>

Divides the result set produced by the FROM clause into partitions to which the RANK function is applied. For the syntax of PARTITION BY, see OVER Clause (Transact-SQL).

<>

Determines the order in which the RANK values are applied to the rows in a partition. For more information, see ORDER BY Clause (Transact-SQL). An integer cannot represent a column when the <> is used in a ranking function.

Example:

Use Vendor

GO

SELECT VendorId, VendorFName, VendorLName,

RANK() Over(PARTITION BY PostedDate ORDER BY VendorId) AS 'RANK'

FROM Vendor ORDER BY PostedDate DESC

GO

7 DENSE_RANK () - Returns the rank of rows within the partition of a result set, without any gaps in the ranking. The rank of a row is one plus the number of distinct ranks that come before the row in question.

Syntax: DENSE_RANK ( ) OVER ([<>] <>)

Arguments: <>

Divides the result set produced by the FROM clause into partitions to which the DENSE_RANK function is applied. For the syntax of PARTITION BY, see OVER Clause (Transact-SQL).

<>

Determines the order in which the DENSE_RANK values are applied to the rows in a partition. An integer cannot represent a column in the that is used in a ranking function.

Example :

Use Vendor

GO

SELECT VendorId, VendorFName, VendorLName,

DENSE_RANK() OVER(PARTITION BY PostedDate ORDER BY VendorId) AS 'DENSE RANK'

FROM Vendor ORDER BY PostedDate DESC

GO

NTILE (integer_expression) - Distributes the rows in an ordered partition into a specified number of groups. The groups are numbered, starting at one. For each row, NTILE returns the number of the group to which the row belongs.

Syntax: NTILE (integer_expression) OVER ([] <>)

Arguments: integer_expression

Is a positive integer constant expression that specifies the number of groups into which each partition must be divided? integer_expression can be of type int, or bigint.

Note:

integer_expression can only reference columns in the PARTITION BY clause. integer_expression cannot reference columns listed in the current FROM clause.

Divides the result set produced by the FROM clause into partitions to which the RANK function is applied. For the syntax of PARTITION BY, see OVER Clause (Transact-SQL).

<>

Determines the order in which the NTILE values are assigned to the rows in a partition. For more information, see ORDER BY Clause (Transact-SQL). An integer cannot represent a column when the is used in a ranking function.

Example :

Use Vendor

GO

SELECT VendorFName, VendorLName,

NTILE(4) OVER(PARTITION BY PostedDate ORDER BY VendorId DESC) AS 'Quartile'

FROM Vendor

GO

 

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